6x^2+33x^2+36x=0

Solution for 6x^2+33x^2+36x=0 equation:

6x^2+33x^2+36x=0

We add all the numbers together, and all the variables

39x^2+36x=0

a = 39; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·39·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*39}=\frac{-72}{78}
=-12/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*39}=\frac{0}{78}
=0
$